Explanation:
When experimenting, the best hypothesis to develop would be a null hypothesis (H₀). A null hypothesis is a statement indicating no change or effect. In this case, it would be;
“There is no effect of temperature on the solubility of a solid in a liquid”
An alternative hypothesis (Hₐ) would be;
“There is an effect of temperature on the solubility of a solid in a liquid”
In this experiment, the null hypothesis would be rejected and the alternative would be accepted. This is because the experiment would show that increased temperatures of the liquid increases solubility of the solid in the liquid.
Answer: 0, 32 , 273
Explanation:
The freezing point of water in degree Celsius, Fahrenheit and Kelvin are in the following order; 0 , 32 , 273
Answer:
sodium hexachloroplatinate(IV)- Na2[PtCl6]
dibromobis(ethylenediamine)cobalt(III) bromide- [Co(en)2Br2]Br
pentaamminechlorochromium(III) chloride-[Cr(NH3)5Cl]Cl2
Explanation:
The formulas of the various coordination compounds can be written from their names taking cognisance of the metal oxidation state as shown above. The oxidation state of the metal will determine the number of counter ions present in the coordination compound.
The number ligands are shown by subscripts attached to the ligand symbols. Remember that bidentate ligands such as ethylenediamine bonds to the central metal ion via two donors.
A molecular size affects the rate of evaporation when the larger the intermolecular forces in a compound, the slower the evaporation rate and this correlates with temperature change.
Molecular size seems to have an effect on evaporation rates in that the larger a molecule gets or grows from a base chemical formula, its evaporation rate will get slower.
<h3>What is the molecular size?</h3>
This is a measure of the area a molecule occupies in three-dimensional space as this relates to the physical size of an individual molecule.
Hence, we can see that a molecular size affects the rate of evaporation the larger the forces, the lower the rate.
Read more about<em> molecular size</em> here:
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