2 years ago

(6x+3)(-5x-6) i need 20 more characters so i'm typing this

Mathematics

1 answer:

Nady [450]2 years ago

4 0

=−30x2−51x−18 the 2 is squared idk how to do it but that’s the answer

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5/ 10 of the students in Sam’s class are girls. Of the girls, 1 /5of them wear glasses. What fraction of all the students wear g

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1/10 because one girl out of ten students wears glasses

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2 years ago

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You make as many expansion packs as you can. With the parts remaining, you could make 1 more expansion pack if you had :

ser-zykov [4K]

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enough time

Step-by-step explanation:

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2 years ago

Taven mixes 18 liters of 14% acid solution with a 35% acid solution, which results in 23% acid solution.

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2 years ago

Help Please :))

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F(x) = 3x²-6x+2
f(2) = ?

f(2) = 3.2²-6.2+2
f(2) = 3.4-12+2
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2 years ago

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In the game of blackjack played with one deck, a player is initially dealt 2 different cards from the 52 different cards in the

Volgvan

Answer:

$P =4.83\%$

Step-by-step explanation:

First we calculate the number of possible ways to select 2 cards an ace and a card of 10 points.

There are 4 ace in the deck

There are 16 cards of 10 points in the deck

To make this calculation we use the formula of combinations

$nCr=\frac{n!}{r!(n-r)!}$

Where n is the total number of letters and r are chosen from them

The number of ways to choose 1 As is:

$4C1 = 4$

The number of ways to choose a 10-point letter is:

$16C1 = 16$

Therefore, the number of ways to choose an Ace and a 10-point card is:

$4C1 * 16C1 = 4 * 16 = 64$

Now the number of ways to choose any 2 cards from a deck of 52 cards is:

$52C2 =\frac{52!}{2!(52-2)!}$

$52C2 = 1326$

Therefore, the probability of obtaining an "blackjack" is:

$P = \frac{4C1 * 16C1}{52C2}$

$P = \frac{64}{1326}$

$P = \frac{32}{663}$

$P =0.0483$

$P =4.83\%$

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2 years ago

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