Answer:
Option 3. 71 ft. is the distance between B and top of the hill.
Step-by-step explanation:
Let the height of the hill is h ft and the distance of A from the hill be x ft and distance from B to hill is y.
It is given distance between A and B is 45 ft. ∠BAO = 65° and ∠ABO = 80°.
We have to find the distance of B from the top of the hill.
Now from ΔACO 
From ΔBCO 
h = 5.67x
Now h = 5.67x = 2.14(45-x)
5.67x = 96.3 - 2.14x
2.14x + 5.67x = 96.3
7.81x = 96.3
x = 96.3/7.81 = 12.33 ft
Therefore 
Therefore 71 ft is the distance between B and the top of the hill.
130 degrees.
ADB = 90 degrees
BDT=40 Degrees
Therefore, TDS = ADB(90)+BDT(40)=130 degrees
The answer to this question is:
You walk an average of 3.2 miles per hour on the way to school and at an average of 4 miles per hour on the way home the total walking time is 18 minutes how far away is the school Round your answer to the nearest hundredth of a mile
<span>.53 mi
</span><span>.133 hrs
Hope This Helped, Markadoodle
Your Welcome :)</span>
Answer:
x=61
Step-by-step explanation:
Because it is a 90 degree angle, you subtract the 29 from 90 and you get 61. You can also put in in this equation and arrive at the same conclusion.
90=X+29
It's a right triangle. Use the pythagorean theorem. 36^2+r^2=(r+12)^2. r=48.
