All integers that are exactly divisible by 2 are called what?

A nurse is investigating the birth weights of non-premature babies. She selects a random sample of 41 such babies, and found a

kherson [118]

Answer:

The 95% confidence interval for the mean birth weight of all non-premature babies is between 3350.4 grams and 3662.4 grams. This means that we are 95% sure that true mean birth weight of all non-premature babies is in this interval.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 41 - 1 = 40

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 40 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.0211

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.0211\frac{494.2}{\sqrt{41}} = 156$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 3506.4 - 156 = 3350.4 grams

The upper end of the interval is the sample mean added to M. So it is 3506.4 + 156 = 3662.4 grams

The 95% confidence interval for the mean birth weight of all non-premature babies is between 3350.4 grams and 3662.4 grams. This means that we are 95% sure that true mean birth weight of all non-premature babies is in this interval.

6 0

2 years ago

PLEASE HELP WILL MARK BRAINLIEST

inysia [295]

Answer: (2, -15)

Step-by-step explanation:

5 0

2 years ago

Use the quadratic formula x^2-5x+3=0

kifflom [539]

Answer:

$x^2 -5x +3 = 0\\\\ x= \frac{-b \pm \sqrt{b^2-4*a*c} }{2a} \\\\b = -5, a = 1 , c = 3\\\\x= \frac{-b + \sqrt{b^2-4*a*c} }{2a} , x= \frac{-b -\sqrt{b^2-4*a*c} }{2a}\\\\x= \frac{5 + \sqrt{25-12} }{2}, x= \frac{5-\sqrt{25-12} }{2}\\\\x= \frac{5+\sqrt{13} }{2}, x= \frac{5- \sqrt{13} }{2}$

5 0

2 years ago

−−→ LO bisects ∠ NLM , LM = 18 , NO = 4 , and LN = 10 . LO → bisects ∠ NLM , LM = 18 , NO = 4 , and LN = 10 . What is the value

Sindrei [870]

Answer:

7.2

Step-by-step explanation:

Given that in triangle LMN, LO is angle bisector of angle L.

LN =10 and LM =18

By angle bisector theorem for triangles we have

LN/LM = NO/MO

Substitute the values for known things and x for MO

We get

10/18 = 4/x

Or cross multiply to get

10x=72

x=7.2

So answer is 7.2

3 0

2 years ago

Simon has 20 quarters and 12 dimes.He wants to purchase ice cream for his friends.An ice cream cone cost $1.00.How many cones ca

Helga [31]

Answer:

6

Step-by-step explanation:

Each ice cream cone costs 4 quarters or 10 dimes, so Simon has ...

20/4 + 12/10 = 5 + 1.2 = 6.2

times the price of an ice cream cone. He can buy 6 cones for his friends.

8 0

2 years ago