Answer:
A. Both the girl and the boy have the same nonzero angular displacement.
Explanation:
Since girl and boy both are standing on the same merry go round so here we can say that boy and girl both will revolve with same angular speed as the speed of the merry go round
so the angular displacement is given as
so here since both has same angular speed that is the speed of the disc so they both will turn by same angle in the same interval of time
So we have correct answer as
A. Both the girl and the boy have the same nonzero angular displacement.
Answer:
T = mg - 
×V×g
Explanation:
Here we have the mass of the ball is given as 
The density of the fluid =
The volume of the ball = V
Acceleration due to gravity = g
According to Archimedes's principle, the upthrust = Weight of fluid displaced
Tension in string = T = weight of ball - upthrust
T = mg - ×V×g
Answer:
Electromagnetic waves
Explanation:
Electromagnetic waves are waves that consist of oscillating electric and magnetic fields, that oscillate perpendicularly to each other and perpendicularly to the direction of propagation of the wave (for such a reason, these waves are also called transverse waves).
Electromagnetic waves always travel in a vacuum at the same speed, called speed of light:
and they are classified into 7 different types, according to their frequency. From lowest to highest frequency, we have:
Radio waves
Microwaves
Infrared
Visible light
Ultraviolet
X-rays
Gamma rays
Therefore, gamma rays, x-rays, visible light and radio waves are all types of electromagnetic waves with different frequencies.
Responder:
20.3 ° C
Explicación:
<u>Según la ley de Charles</u>: <em>cuando la presión sobre una muestra de gas seco se mantiene constante, la temperatura y el volumen estarán en proporción directa.
</em>
Paso uno:
datos dados
Temperatura T1 = 20 ° C
Temperatura T2 =?
Volumen V1 = 12.2 cm ^ 3
Volumen V2 = 12.4 cm ^ 3
Aplicar la relación temperatura y volumen
sustituyendo tenemos
Cruz multiplicar tenemos
Temperatura delle braci 20.3°C
Answer:
1,85 m / s²
Explanation:
De la pregunta anterior, se obtuvieron los siguientes datos:
Velocidad inicial (u) = 40 km / h
Hora inicial (t₁) = 0
Tiempo final (t₂) = 6 s
Velocidad final (v) = 0
Aceleración (a) =?
A continuación, convertiremos 40 km / ha m / s. Esto se puede obtener de la siguiente manera:
1 km / h = 0,2778 m / s
Por lo tanto,
40 km / h = 40 km / h × 0,2778 m / s / 1 km / h
40 km / h = 11,11 m / s
Por tanto, 40 km / h equivalen a 11,11 m / s.
Finalmente, determinaremos la aceleración del móvil durante el período en el que desaceleró. Esto se puede obtener de la siguiente manera:
Velocidad inicial (u) = 11,11 m / s
Hora inicial (t₁) = 0
Tiempo final (t₂) = 6 s
Velocidad final (v) = 0
Aceleración (a) =?
a = (v - u) / (t₂ - t₁)
a = (0 - 11,11) / (6 - 0)
a = - 11,11 / 6
a = –1,85 m / s²
Por tanto, la aceleración del móvil durante el período en el que se ralentizó es de –1,85 m / s²
