How to find the inverse of the function f(x)=2x-3 ? Please

2 answers:

8 0

F(x)=2x-3
y=2x-3
x=(y+3)/2

f⁻¹(x) = (x+3) / 2

NISA [10]2 years ago

3 0

$f(x)=2x-3\\\\y=2x-3\\\\-2x=-y-3\ \ \ \ /:(-2)\\\\x=\frac{1}{2}y+\frac{3}{2}\\\\f^{-1}(x)=\frac{1}{2}x+\frac{3}{2}$

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nikklg [1K]

Hey there!

Firstly, you have to $\bold{simplify}$ each of the sides of your equation
$\bold{6-2p-p+9\downarrow}$
$\bold{6+(-2p)=p+9\downarrow}$
$\rightarrow\bold{-2p+6=p+9}$
Now that you have that portion out of the way, we could move on to our second step... which is to $\bold{subtract}$ by the value of $\bold{p}$ on each of your sides
$\bold{-2p+6-p-p+9-p\downarrow}$
$\rightarrow\bold{-3p+6-9}$ (you get this because we solve the particular equation we added above)
Thirdly, you have to $\bold{subtract}$ by the number $\bold{6}$ on each of your sides
$\bold{-3p+6-6=9-6\downarrow}$
$\bold{Cancel:6-6}$ because it equals to $\bold{0}$
$\bold{Keep:9-6}$ because it brings us closer and closer to the answer of $\bold{p}$
Fourthly, we have to $\bold{divide}$ by the number $\bold{-3}$ on each of your sides
$\bold{\frac{-3p}{-3}=\frac{3}{-3}}$
$\boxed{\boxed{\bold{Answer:p=-1}}}$ $\checkmark$