Answer:
16.6 N
Explanation:
m = 0.52 kg, v₀ = 0, v = 8.6 m/s, t = 0.27 s
a = (v - v₀)/t
F = ma = m(v - v₀)/t = 0.52 (8.6 - 0)/0.27 = 16.6 N
Hydraulic conductivity (K) is a property of soil<span> that describes the ease with which water can move through </span>pore<span> spaces. It depends on the permeability of the material (</span>pores, compaction) and on the degree of saturation. Saturated hydraulic conductivity, Ksat<span>, describes water movement through saturated media.</span><span />
The answer to this question is B I think
Answer:
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Explanation:
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Answer:
Explanation:
We have here values from SI and English Units. I will convert the units to English Units.
We hace for the power P,
we have other values such and (specific weight of the water), and 0.85 for \eta
We need to figure the flow rate of the water (V) out, that is,
Where is the turbine efficiency, at which is,
Replacing,
With this value (the target of this question) we can also calculate the mass flow rate of the waters,
through the density and the flow rate,
converting the slugs to lbm, 1slug = 32.174lbm, we have that the mass flow rate of the water is,