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2 years ago

List 3 to 5 ways to reduce friction

2 answers:

8 0

Make the surfaces smoother. Rough surfaces produce more friction and smooth surfaces reduce friction
Lubrication is another way to make a surface smoother
Make the object more streamlined
Reduce the forces acting on the surfaces
Reduce the contact between the surfaces.

svp [43]2 years ago

5 0

1.Make the surfaces smoother. Rough surfaces produce more friction and 2.smooth surfaces reduce friction.

3.Lubrication is another way to make a surface smoother.

4.Make the object more streamlined

5.Reduce the forces acting on the surfaces.

6.Reduce the contact between the surfaces.

hope this helps ;)

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A positively charged particle initially at rest on the ground accelerates upward to 160 m/s in 2.10 s. The particle has a charge

mamaluj [8]

Answer:

The magnitude of the electric field is $8.6\times10^{2}\ N/C$

Explanation:

Given that,

Time t = 2.10 s

Speed = 160 m/s

Specific charge =Ratio of charge to mass = 0.100 C/kg

We need to calculate the acceleration

Using equation of motion

$a=\dfrac{v-u}{t}$

Put the value into the formula

$a=\dfrac{160-0}{2.10}$

$a=76.19\ m/s^2$

We need to calculate the magnitude of the electric field

Using formula of electric field

$E=\dfrac{F}{q}$

$E=\dfrac{ma}{q}$

$E=\dfrac{a+g}{\dfrac{q}{m}}$

Put the value into the formula

$E=\dfrac{76.19+9.8}{0.100}$

$E=8.6\times10^{2}\ N/C$

The direction is upward.

Hence, The magnitude of the electric field is $8.6\times10^{2}\ N/C$

4 0

3 years ago

Read 2 more answers

A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket

Nadusha1986 [10]

Answer:

A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket. The bolt hits the ground 6.10s later.

Explanation:

A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket. The bolt hits the ground 6.0 s later. What was the rocket’s acceleration?

6 0

2 years ago

Which goes faster? * light in space sound in air sound in space light in water

andrezito [222]

Answer:

Hello! Your answer is, sound in the air is faster

Explanation:

The speed of sound through air is about 340 meters per second. It's faster through water and it's even faster through steel. Light will travel through a vacuum at 300 million meters per second. So they're totally different scales.

Hope I helped! Ask me anything if you have any questions! Brainiest plz. Hope you make an 100% and have a nice day! -Amelia♥

8 0

2 years ago

a car has a mass of 1.00 x 10^3 kilograms and it has an acceleration of 4.5 meters/second what is the net force on the car

Reptile [31]

The answer is 4.5 x10^3 newtons.

6 0

2 years ago

Read 2 more answers

You stand on a frictional platform that is rotating at 1.8 rev/s. Your arms are outstretched, and you hold a heavy weight in eac

dusya [7]

Answer:

20.62361 rad/s

489.81804 J

Explanation:

$I_i$ = Initial moment of inertia = 9.3 kgm²

$I_f$ = Final moment of inertia = 5.1 kgm²

$\omega_i$ = Initial angular speed = 1.8 rev/s

$\omega_f$ = Final angular speed

As the angular momentum of the system is conserved

$I_i\omega_i=I_f\omega_f\\\Rightarrow \omega_f=\dfrac{I_i\omega_i}{I_f}\\\Rightarrow \omega_f=\dfrac{9.3\times 1.8}{5.1}\\\Rightarrow \omega_f=3.28235\ rev/s=3.28235\times 2\pi=20.62361\ rad/s$

The resulting angular speed of the platform is 20.62361 rad/s

Change in kinetic energy is given by

$\Delta K=\dfrac{1}{2}(I_f\omega_f^2-I_i\omega_i^2)\\\Rightarrow \Delta K=\dfrac{1}{2}(5.1\times (20.62361)^2-9.3\times (1.8\times 2\pi)^2)\\\Rightarrow \Delta K=489.81804\ J$

The change in kinetic energy of the system is 489.81804 J

As the work was done to move the weight in there was an increase in kinetic energy

6 0

2 years ago