(6, 3), (7-4) find the slope

Mathematics

1 answer:

Hunter-Best [27]2 years ago

4 0

Answer:

-7

Step-by-step explanation:

Y-Y $\frac{-4-3}{7-6}$

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Point T is the midpoint of JH. The coordinate of T is (0, 5) and the coordinate of J is (0, 2). The coordinate of H is:

aev [14]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&J&(~ 0 &,& 2~) 
% (c,d)
&H&(~ x &,& y~)
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{ x_2 + x_1}{2}\quad ,\quad \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left(\cfrac{x+0}{2}~~,~~\cfrac{y+2}{2} \right)=\stackrel{midpoint~T}{(0~,~5)}\implies 
\begin{cases}
\cfrac{x+0}{2}=0\\\\
\boxed{x=0}\\
------\\
\cfrac{y+2}{2}=5\\\\
y+2=10\\
\boxed{y=8}
\end{cases}$

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Answer:

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Step-by-step explanation:

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2 years ago

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seropon [69]

Answer:

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Step-by-step explanation:

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Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, -1).

ira [324]

Line:
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Answer:

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