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2 years ago

6

Michael added 15 fish to his pond over a period of 5 days he added the same number of fish each day what was the change in the n

umber of fish in the pond each day

1 answer:

Yuri [45]2 years ago

5 0

Answer:

3

Step-by-step explanation:

15 fish / 5 days = 3 fish per day

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r-ruslan [8.4K]

Answer:

number less than 3=1 and 2

so 2/6 = 1/3 in lowest terms

then rolling a 6 =

there is only one 6 so it will be 1/6

I hope I helped

7 0

2 years ago

Which mapping shows a function

Alja [10]

The second one because there is all the inputs are different. There is one input for every output.

4 0

2 years ago

Which equation represents the volume of a cone with the same base and height as the cylinder below?

Firdavs [7]

Answer:

Volume of cone = (1/3) * Volume of cylinder

Step-by-step explanation:

Use the formulas

Volume of cone = (1/3)* π r^2 *h

Volume of cylinder = π r^2 *h

Therefore

Volume of cone = (1/3) * Volume of cylinder

7 0

2 years ago

abruzzese [7]

Answer:

a) 30 kangaroos in 2030

b) decreasing 8% per year

c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo

Step-by-step explanation:

We assume your equation is supposed to be ...

P(t) = 76(0.92^t)

__

a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30

In the year 2030, the population of kangaroos in the province is modeled to be 30.

__

b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.

The population is decreasing by 8% each year.

__

c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.

P(100) = 75(0.92^100) = 76(0.0002392)

P(100) ≈ 0.0182, about 1/55th of a kangaroo

5 0

3 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

or

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .

Observe the image below.

7 0

2 years ago