Answer:
83% remains in the box
Step-by-step explanation:
Here, we are interested in calculating the percentage of donuts remaining in the box.
From the question, we are told that 2 was eaten, the number of donuts left = 12-2 = 10 donuts
The percentage of donuts left would be;
Number of donuts left/Total no of donuts * 100%
= 10/12 * 100 = 83.33
Which is 83% to the nearest whole number percentage
Answer:
The correct option is;
26.8
Step-by-step explanation:
The given parameters are;
The perpendicular bisectors of the sides of ΔMNP = Segments OQ, OR, and OS
Therefore;
in Segment MN, segment QM = segment QN, by definition of bisected line
Segment OQ = Segment OQ by reflexive property
∠OQM = ∠OQN = 90° by definition of perpendicular bisector
∴ ΔOQN ≅ ΔOQM, by SAS rule of congruency
Segment MO ≅ Segment ON by Congruent Parts of Congruent Triangle are Congruent, CPCTC
Segment MO = Segment ON = 26.8, by definition of congruency
Segment MO = 26.8
7.
Discounted price X
————————— = ———
Original Price 100
45 x
—- = —-
72 100
Cross multiply
45 times 100= 4500
72 times x= 72x
72x=4500
Divide
4500/72= 62.5%
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Subtract .018 from 9 to get the answer
9 - .018 = 8.982