The answer is C, i just took the k-12 test~
4.22 grams.
1. First find out how much AgNO3 weighs with one mole (107.87 g Ag + 14.007 g N + 48 g O = 169.89 grams)
2. Find the percent of Ag you have. So, (107.87 g/mol Ag)/(169.89 g/mol AgNO3)= 0.63 * 100 = 63%.
3. If you have 6.7 grams total, you know 63% of it is going to be silver, so just multiply 6.7 grams by .63 and you get 4.22 g Ag
NaOH + CH3COOH -> CH3COONa + H20
Answer :
Option D) 2.50 X Mol/(L s)
Explanation: While calculating the average reaction rate for the given reaction in terms of Cl;
.
using the rate equation which is;
=
=
2.50 X Mol/(L s)
Answer:
I think the answer is 729 cubic millimeters.