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2 years ago

When a metallic element is converted to a positive ion during a chemical reaction with oxygen, the element is said to be?

Chemistry

1 answer:

Orlov [11]2 years ago

5 0

The metal is being oxidized.

Metals- along with other elements- are neutral and have oxidation state of $0$ in their respective elementary states.

Metal atoms can lose electrons to electronegative elements such as oxygen on exposure. Atoms that have lost one or more negatively-charged electrons are no longer neutral and demonstrate a positive charge. Those atoms have converted to positively charged ions or cations.

Oxidation is the process of losing electrons whereas Reduction refers to the process of gaining electrons. "OIL RIG." Metal atoms here lose electrons and are thus oxidized.

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Why vitamin A(retinol) transported by chylomicrons ?

OLga [1]

Answer:

from the small intestine (RE = retinyl ester; ROH = ret- inol. CM = chylomicron remnant). is split at least one intact molecule of retinol, retinal.

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2 years ago

Use one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calcu

stealth61 [152]

Answer:

Explanation:

Use one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calculate the value of the rate constant at 25 °C. Alternatively, you can simply extrapolate the straight line plot of ln(k) vs. 1/T in your notebook to 1/298 , read off the value of ln(k), and determine the value of k. Please put your answer in scientific notation. slope=-12070, Ea=100kJ/mol, k= 0.000717(45C), 0.00284(55C), 0.00492(65C), 0.0165(75C), 0.0396(85C)

Explanation;

According to Arrhenius equation:

i.e. ln(k2/k1) = -Ea/R (1/T2 - 1/T1)

Where, k1 = 0.000717, T1 = 45 oC = (45+273) K = 318 K

T2 = 25 oC = (25 + 273) K = 298 K

i.e. ln(k2/0.000717) = -12070 (1/298 - 1/318)

i.e. ln(k2/0.000717) = -2.54738

i.e. k2/0.000717 = $e^{-2.54738}$

= 0.078286

Therefore, the required constant (k2) = 0.078286 * 0.000717 = $5.61*10^-^5$

6 0

2 years ago

Make sure to show your answer using correct units and sig figs. (all of the

allochka39001 [22]

Answer:

1. 84g.mol`¹

2. 342g.mol`¹

3 0

2 years ago

I need three examples of objects with high density and three with low density!!

Anuta_ua [19.1K]

Answer:

For example, a suitcase jam-packed with clothes and souvenirs has a high density, while the same suitcase containing two pairs of underwear has low density. Size-wise, both suitcases look the same, but their density depends on the relationship between their mass and volume. Mass is the amount of matter in an object.

5 0

2 years ago

Read 2 more answers

Complete and balance the molecular equation for the reaction of aqueous sodium carbonate, Na 2 CO 3 Na2CO3 , and aqueous nickel(

antoniya [11.8K]

Answer: The net ionic equation is written below.

Explanation:

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of sodium carbonate and nickel (II) chloride is given as:

$Na_2CO_3(aq.)+NiCl_2(aq.)\rightarrow 2NaCl(aq.)+NiCO_3(s)$

Ionic form of the above equation follows:

$2Na^{+}(aq.)+CO_3^{2-}(aq.)+Ni^{2+}(aq.)+2Cl^{-}(aq.)\rightarrow NiCO_3(s)+2Na^+(aq.)+2Cl^-(aq.)$

As, sodium and chloride ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$Ni^{2+}(aq.)+CO_3^{2-}(aq.)\rightarrow NiCO_3(s)$

Hence, the net ionic equation is written above.

3 0

3 years ago