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2 years ago

5

A rectangle has a length that is 4 ft more

2 answers:

Ludmilka [50]2 years ago

6 0

Answer:

length = 14 width = 10

Step-by-step explanation:

48/4=12

10+10+14+14=48

Mars2501 [29]2 years ago

4 0

Width = W = 10 ft

Length = L = 14 ft

P = perimeter = 48 ft

Explanation:

P rectangle = 2L+ 2W
L = W + 4
P = 48

Substitute into formula:
P rectangle = 2L + 2W
48 = 2( W + 4 ) + 2W
48 = 2W + 8 + 2 W
48= 4W + 8
48 - 8 = 4W
40 = 4W
W = 40/4 = 10
W = 10

The rectangle has a length that is 4 ft more than its width : L = W + 4

Substitute : L = 10 + 4 = 14
L = 14 ft

I hope this help!!!

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2 years ago

Answers and work for answers please

larisa [96]

Answer:

1) 5 2) 6 3) 1.25 or -1.75

Step-by-step explanation:

1. x^2 - 25 = 0

x^2 - 25 = 0

First, add 25 to both sides!

x^2 = 25

Now square root both sides.

x = 5

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First, square root both sides.

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3. Quadratic Formula = -b ± $\sqrt{b^{2}-4ac }$ / 2a

Substitute in:

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8 0

1 year ago

Four time a number r plus half a number s equals 12. Twice the number r plus one fourth of the numbers s equals 8. What are the

Snezhnost [94]

The system of equations have no solution.

Explanation:

The equations are $4r+\frac{1}{2}s=12$ and $2r+\frac{1}{4} s=8$

To find the two numbers, let us solve the equations using substitution method.

From the equation $2r+\frac{1}{4} s=8$ , let us determine the value of r,

$\begin{aligned} 2 r+\frac{1}{4} s &=8 \\ 2 r &=8-\frac{1}{4} s \\ r &=\frac{1}{2}\left(8-\frac{1}{4} s\right) \\ r &=4-\frac{1}{8} s \end{aligned}$

Let us substitute the value of r in $4r+\frac{1}{2}s=12$ , we get,

$\begin{aligned} 4\left(4-\frac{1}{8} s\right)+\frac{1}{2} s &=12 \\ 16-\frac{1}{2} s+\frac{1}{2} s &=12 \\ 16 &=12 \end{aligned}$

which is not possible.

This means that the system has no solution.

6 0

2 years ago