2 years ago

Factor 2s^3-27-18s+3s^2 by grouping

Mathematics

2 answers:

a_sh-v [17]2 years ago

7 0

(2s+3)(s+3)(s-3)-----------

bazaltina [42]2 years ago

3 0

2s^3-27-18s+3s^2
(2s^3+3s^2)+(-18s-27)
s^2(2s+)-(2s+3)
(2s+3)(s^2-9)
(s+3)(s-3)(2s+3)

I hope this helps!!!!!!!

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Evgesh-ka [11]

Answer:

D-last pic

Step-by-step explanation:

Check the rate of change in the f(x) column.

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Correct option is D

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2 years ago

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weqwewe [10]

Answer:

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2 years ago

which of the following properties could be used to rewrite the expression (2/3•1/5)•5/2 as 2/3•(5/2•(5/2•1/5) sorry to ask Su ma

slamgirl [31]

The original expression is given by:
$( \frac{2}{3}*\frac{1}{5})*\frac{5}{2}$
The correct way to rewrite the expression is given by:
$\frac{2}{3}*(\frac{5}{2}*\frac{1}{5})
$
For this, we use two properties:

Associative property:
The way of grouping the factors does not change the result of the multiplication:
$\frac{2}{3}*(\frac{1}{5}*\frac{5}{2})$

Commutative property:
The order of the factors does not vary the product:
$\frac{2}{3}*(\frac{5}{2}*\frac{1}{5})$

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2 years ago

Write<br> 83<br> 50<br> as a decimal.

Katyanochek1 [597]

Answer:

0.83,0.50

Step-by-step explanation:

Since there are 2 digits in 83, the very last digit is the "100th" decimal place.

So we can just say that .83 is the same as 83/100.

So your final answer is: .83 can be written as the fraction

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2 years ago