The correct answer is D, they are reviewed by experts.
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Answer:
62.586 gram
Explanation:
moles of Al(OH)3 = mass / molar mass = 35.1 / (27+17x3) = 0.45 mol
moles of H2SO4 = mass / molar mass = 53.94 / (2+32+16x4) = 0.55 mol
H2SO4 is the limiting reagent (reacts completely)
⇒ moles of Al2(SO4)3 is worked out by moles of H2SO4
moles of Al2(SO4)3 = moles of H2SO4 / 3 = 0.183 mol
mass of Al2(SO4)3 = mole x molar mass = 0.183 x (27x2 + 96x3) = 62.586 gram
Answer:
this is the required answer look it once
Answer: 10 moles/kg.
Explanation:
Given, Mass of solute = 24.2 g
Molar mass of solute = 24.2 g/mol
Mass of solvent = 100.0g = 0.1 kg [1 g=0.001 kg]
Hence, the molality of the resulting solution is 10 moles/kg.
Answer:
4.5 g
Explanation:
Given,
Moles of water = 0.25 moles
Molar mass of water () = = 18 g/mol
The formula for the calculation of moles is shown below:
Thus,
<u>Mass of water in 0.25 moles = 4.5 g</u>