Answer : The mass of precipitate will be, 12.4 grams.
Explanation :
First we have to calculate the moles of
Now we have to calculate the moles of
The balanced chemical reaction is:
From then balanced chemical reaction we conclude that,
As, 2 moles of react to give 1 mole of
So, 0.075 moles of react to give mole of
Now we have to calculate the mass of
Molar mass of = 331.73 g/mole
Therefore, the mass of precipitate will be, 12.4 grams.