The smaller square has length of 4. So its perimeter is 4*4 = 16
The larger square has length of 8 and its perimeter is 8*4 = 32
The scale factor is 2. Since the larger square is twice the size of the smaller square (Or you can say that the scale factor is 1/2 if you are looking at the perspective of the larger square to the smaller square).
Hi, I'm happy to help!
First, we need to find BC. We know, because B is the midpoint of AC, that AB and BC are congruent, or the same length. We are told that AB is 3.
<u>So, BC is 3 also.</u>
Next, we need to find AC. AC is a combination of AB and BC, so, we just add them.
3+3=6
<u>AC is 6.</u>
Finally, we need to find DE. We know that AC and CE are congruent because of this sign: ≅. This means they are the same length. We can then know that CE is 6 also. To find DE we need to take the length of CD away from CE. We know that CD is 2, so now, we subtract.]
6-2=4
<u>DE is 4.</u>
<u></u>
I hope this was helpful, keep learning! :D
Step-by-step explanation:
Volume of displaced water = (10cm)(10cm)(1.6cm)
= 160 cm^3
density = mass/vol of displaced water
= 3088 grams/160 cm^3
= 19.3 g/cm^3
P.S. This is most likely a pure gold medallion.
If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
Learn more about angles at brainly.com/question/25716982
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Answer:
$425
Step-by-step explanation:
45,765 divided by 26 equals 1,760.192307692308
34,715 divided by 26 equals 1,335.192307692308
1,760.192307692308-1,335.192307692308=425
