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2 years ago

Round the number 63,825 On the hundreds place

Mathematics

2 answers:

anzhelika [568]2 years ago

7 0

Answer:

63,800

Step-by-step explanation:

Mrac [35]2 years ago

6 0

Answer:

63,800

hope this helps :3

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X - 5(x - 1) = x - (2x - 3)

m_a_m_a [10]

X=2/3 I hope this helps

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2 years ago

Read 2 more answers

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

$y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0$

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

$p(x) = \dfrac{(x+2)}{(x^2-4)^2} \$

$p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \$

$p(x) = \dfrac{1}{(x+2)(x-2)^2}$

Also;

$q(x) = \dfrac{7}{(x^2-4)^2}$

$q(x) = \dfrac{7}{(x+2)^2(x-2)^2}$

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

$\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}$

$\implies \dfrac{1}{16}$

$\lim \limits_{x \to-2} (x+ 2)^2 q(x) = \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{7}{(x-2)^2}$

$\implies \dfrac{7}{16}$

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

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2 years ago

A customer went to a garden shop and bought some potting soil for $17.50 and 4 shrubs. The total bill was $53.50. Choose the equ

olga2289 [7]

4x + 17.50 = 53.50

the prices of each shrub would be 9 dollars each

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2 years ago

The sum of two numbers is 3 and the product is -40. Find the numbers . List each number separates by a comma

pshichka [43]

it is 8, and -5 that is the answer

5 0

2 years ago

1. What is the value of x? Do not convert to decimal. Keep your answer in exact (radical) form. Show all of your work. This is P

lesya [120]

Answer:

The value of x is $\sqrt{113}$ .

Step-by-step explanation:

It is given that hypotenuse is $\sqrt{177}$ . So, the legs would be x and 8.

Let's use Pythagoras theorem,

$a^{2} +b^{2} =c^{2}$

Plug in the numbers to solve for x.

$x^{2} +8^{2} =\sqrt{177} ^{2}$

Simplify it

$x^{2} +64 =177$

Subtract both sides 64.

$x^{2} =113$

Take square root on both sides

x= $\sqrt{113}$

We can not simplify the radical.

So, let's keep this as answer.

6 0

2 years ago