Answer:197.504 N
Explanation:
Given
Two Charges with magnitude Q experience a force of 12.344 N
at distance r
and we know Electrostatic force is given
Now the magnitude of charge is 2Q and is at a distance of
F'=16F
F'=197.504 N
Answer:
The magnitude of acceleration is reduced.
Explanation:
Force is defined as push or pull
The force is said to be<em> balance force </em>if the force are equal in size but opposite in direction. ie the object does not move or move with constant speed.
The force are to be<em> unbalanced force </em>if the force cause change in motion. ie the object has force greater than zero and has acceleration.
According to <em>Newton second law of motion </em>, acceleration depends on force acting on the object and mass of object.
F=ma
a=
When unbalanced force act on the mass of object it reduces magnitude of acceleration without changing the direction.
Complete Question
The diagram for this question is shown on the first uploaded image
Answer:
a E =
b E =
c E = 0 N/C
d
e
f V =
g
h
i
Explanation:
From the question we are given that
The first charge
The second charge
The first radius
The second radius
And
The objective is to obtain the the magnitude of electric for different cases
And the potential difference for other cases
Considering a
r = 4.00 m
Considering b
This implies that the electric field would be
This because it the electric filed of the charge which is below it in distance that it would feel
=
Considering c
r = 0.200 m
=>
The electric field = 0
This is because the both charge are above it in terms of distance so it wont feel the effect of their electric field
Considering d
r = 4.00 m
=>
Now the potential difference is
This so because the distance between the charge we are considering is further than the two charges given
Considering e
r = 1.00 m
Considering f
Considering g
Considering h
Considering i
Answer:
making sure that you change one factor at a time while keeping all other conditions the same
Explanation:
Answer:
non linear square relationship
Explanation:
formula for centripetal force is given as
a = mv^2/r
here a ic centripetal acceleration , m is mass of body moving in circle of radius r and v is velocity of body . If m ,and r are constant we have
a = constant × v^2
a α v^2
hence non linear square relationship