Answer:
Gas neither has definite volume nor definite shape.
Assume there are 100g of the compound.
Mass of carbon:20.01g
Mass of oxygen:79.99g
Number of mole of carbon:20.01/12=1.6675mol
Number of mole of oxygen:79.99/32=2.4996875mol
Mole ratio between carbon and oxygen:
1.6675/1.6675:2.4996875/1.6675
=1:1.499062969
1x2:1.499062969x2
=2:2.998125937
≈2:3
Hence, the empirical formula:
C2O3
The pressure of the tyre after the temperature change is 0.89atm. Details about pressure can be found below.
<h3>How to calculate pressure?</h3>
The pressure of the tyre can be calculated using the following equation:
P1/T1 = P2/T2
Where;
- P1 = initial pressure
- P2 = final pressure
- T1 = initial temperature
- T2 = final temperature
According to this question, a tyre at 21°C (294K) has a pressure of 0.82 atm. Its temperature decreases to –3.5°C (269.5K).
0.82 × 294 = P2 × 269.5
241.08 = 269.5P2
P2 = 241.08 ÷ 269.5
P2 = 0.895atm
Therefore, the pressure of the tyre after the temperature change is 0.89atm.
Learn more about pressure at: brainly.com/question/23358029
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