Answer:
a. For $250000 machine option the IRR= 6.08% and NPV =$0
For $350000 machine option the IRR =5.39% and NPV= $0, option for $250000 is the more preferred option.
b. Option For $250000 is the better option as it is closest to the cost of capital and costs the company less to take it. the IRR is directly proportional to the future cash flows
Explanation:
a.For $250000 machine we will start by calculating the future value of investing in the equipment to see how much the total amount the company will get in over 10 years if it were to buy this machinery so we will find the sum of all cash flows over the 10 year period therefore it will be $45100x10 years=$451000 as the company gets a stable cash flow over the ten year period of the equipment's useful life, we know that the net present value of the equipment will be $0 as the equipment will be used up in 10 years time . Now we will use the future value formula to calculate the IRR which is :
Fv is the sum of the future cash flows of the equipment $451000
Pv is the cost of the equipment $250000
IRR is the internal rate of return of the equipment during the course of its 10 year useful life. which is what we are looking for.
n is the useful life of the equipment which is 10 years.
now we substitute on the above mentioned formula and solve for IRR:
$451000 = $250000(1+IRR)^10 ,divide both sides by $250000
$451000/$250000 = (1+IRR)^10 ,find the tenth root of both sides
1.060775922 = 1+IRR subtract by 1 both sides
0.060775922 = IRR multiply by 100
6.08 % = IRR rounded off to two decimal places.
For $350000 the net present value is $0 as after 10 years the equipment will be used up so now we calculate the IRR as above to see what the rate of return on this equipment is firstly we get the sum of cash flows for 10 years for this equipment (Fv) = $72500+$65500+$73800+$71500+$69800+$75500+$31000+$47500+$55500+$29200= $591800
Now we use the formula Fv= Pv (1+IRR)^n
where Pv is the equipment cost $350000
IRR is the internal rate of return we will calculate
n is the useful life of the equipment 10 years
now we substitute and solve for IRR :
$591800 = $350000(1+IRR)^10
$591800/$350000 = (1+IRR)^10 then we get the tenth root of both sides
1.053927391 = 1+IRR
0.053927391 = IRR
5.39% = IRR
the more preferred project is the one for $250000 as it has a greater IRR which is also closer to the cost of capital of 10%.
b. When the Internal rate of return is big then the cash flows also increase in value but when the IRR is small then it gives a smaller overall cash flows even when the equipment costs much more in this case.