Ask question

Ask question

All categories

3 years ago

14

Which is the best reason why 3/5 is the exact quotient for 1/2 divided by 5/6

1 answer:

nydimaria [60]3 years ago

4 0

So when ur trying to divide fractions that can't really "happen" for one u may not get the correct answer so u (KCF) which would mean "keep change flip" so this is what u should get
$\frac{1}{2} \times \frac{6}{5}$
See what we did there? We switch the second fraction and instead of division we did multiplication so then if u multiply across you should get
$\frac{6}{10}$
Then find the greatest common factor which is 2 then divide both of them by two straight across then u would get
$\frac{3}{5}$
Cause 6 divided by 2 =3
And 10 ÷2 =5

You might be interested in

Which transformation carries the pentagon onto its

svetoff [14.1K]

C it’s I think lol!!!!!^^*

6 0

2 years ago

Solve the system: <br> 2x+6y=36<br> x+4y=20

Assoli18 [71]

<u>Let's solve this problem step-by-step</u>

<u>Let's set</u>:

2x + 6y = 36 -- equation 1

x + 4y = 20 -- equation 2

(equation 2) * 2

2x + 8y = 40 -- equation 3

(equation 3) - (equation 1)

2y = 4

y = 2 -- equation 4

Plug (equation 4)'s value of y into (equation 2)

x + 4(2) = 20

x = 20 - 8

x = 12

<u>Thus x = 12 and y = 2</u>

<u>Let's check, by substituting these values</u>

$2x + 6y = 36\\2(12)+6(2) = 36\\24+12=36\\36=36\\\\x+4y=20\\12+4(2)=20\\12+8=20\\20=20$

<u>Answer: x = 12 and y = 2</u>

Hope that helps!

5 0

1 year ago

Simplify your answer and write it as a proper fra<br> as a whole or mixed number.<br> -7+ – 2 = ?

ZanzabumX [31]

the answer is -9

hope it helps

4 0

2 years ago

Read 2 more answers

Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

5 0

2 years ago

How many times can 5 go into 78

creativ13 [48]

Answer:

15.6

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers