Answer:
2.40
Step-by-step explanation:
<em>Answer:</em>
<h2>
<em>x=</em><em>6</em><em>√</em><em>2</em></h2>
<em>please </em><em>see</em><em> the</em><em> attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em><em>.</em><em>.</em><em>.</em>
<em>Hope </em><em>it</em><em> helps</em><em>.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em>
The area of the rectangular is expressed in the formula A = l*w where l is the length and w is the width. from the first satement, l = 2 + w; then A = (2+w)*w = 2w + w^2. If A is equal to 168, then w should be equal to 12 feet and l is equal to 14 feet. Hence the width due to the border limits is 12- 2*2 equal to 8 feet
Answer:
P ( -1 < Z < 1 ) = 68%
Step-by-step explanation:
Given:-
- The given parameters for standardized test scores that follows normal distribution have mean (u) and standard deviation (s.d) :
u = 67.2
s.d = 4.6
- The random variable (X) that denotes standardized test scores following normal distribution:
X~ N ( 67.2 , 4.6^2 )
Find:-
What percent of the data fell between 62.6 and 71.8?
Solution:-
- We will first compute the Z-value for the given points 62.6 and 71.8:
P ( 62.6 < X < 71.8 )
P ( (62.6 - 67.2) / 4.6 < Z < (71.8 - 67.2) / 4.6 )
P ( -1 < Z < 1 )
- Using the The Empirical Rule or 68-95-99.7%. We need to find the percent of data that lies within 1 standard about mean value:
P ( -1 < Z < 1 ) = 68%
P ( -2 < Z < 2 ) = 95%
P ( -3 < Z < 3 ) = 99.7%
I think that x = 37/19
22x+54=−20+60x
Step 1: Simplify both sides of the equation.
22x+54=60x−20
Step 2: Subtract 60x from both sides.
22x+54−<u>60x</u>=60x−20−<u>60x</u>
−38x+54=−20
Step 3: Subtract 54 from both sides.
−38x+54−<u>54</u>=−20−<u>54</u>
−38x=−74
Step 4: Divide both sides by -38.
−38x/ <u>−38</u> = −74/<u>−38</u>
x=37/19