The order of the first ionization energy of the given elements from highest to lowest is
Further Explanation:
The energy that is needed to remove the most loosely bound valence electrons from the isolated neutral atom of the gas is known as the ionization energy. It is denoted by IE. The value of IE is related to the ease of removing the outermost valence electrons. If these electrons are removed so easily, small ionization energy is required and vice-versa. It is inversely proportional to the size of the atom.
Ionization energy is further represented as first ionization, second ionization and so on. When the first electron is removed from a neutral, isolated gaseous atom, the energy needed for the purpose is known as the first ionization energy, written as . Similarly, when the second electron is removed from the positively charged species (cation), the ionization energy is called the second ionization energy and so on.
Potassium, calcium, germanium, selenium, bromine, and krypton belong to the same period of the periodic table.
Along a period, the atomic number increases but the number of shells remains the same while moving from left to right.
The number of protons, as well as the electrons, increases with the increase in the atomic number but the extra electrons are added in the same shell. Due to the high positive nuclear charge, the effective nuclear charge also increases. This results in an increase in the first ionization energy. So krypton will have the highest first ionization energy, followed by bromine, selenium, germanium, calcium, and potassium will have the lowest ionization energy.
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Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Periodic classification of elements
Keywords: first ionization energy , K, Ca, Ge, Se, Br, Kr, protons, electrons, atomic number, isolated, neutral, atom, nuclear charge.