The correct answer is the first option.
If you want to use elimination, you can sum the two equations for example, so that the x's simplify:
Plug this value for y in one of the equations to derive the value of x:
So, the solution is
The answer is 30, can I get the brainliest answer
Answer:
Step-by-step explanation:
<u>Errors in Algebraic Operations
</u>
It's usual that students make mistakes when misunderstanding the application of algebra's basic rules. Here we have two of them
- When we change the signs of all the terms of a polynomial, the expression must be preceded by a negative sign
- When multiplying negative and positive quantities, if the number of negatives is odd, the result is negative. If the number of negatives is even, the result is positive.
- Not to confuse product of fractions with the sum of fractions. Rules are quite different
The first expression is
Let's arrange into format:
We can clearly see in all of the factors in the expression the signs were changed correctly, but the result should have been preceeded with a negative sign, because it makes 3 (odd number) negatives, resulting in a negative expression. The correct form is
Now for the second expression
Let's arrange into format
It's a clear mistake because it was asssumed a product of fractions instead of a SUM of fractions. If the result was correct, then the expression should have been
Answer:
0.037037037037037 i think
Step-by-step explanation:
Answer:
Solution tends to infinity
Step-by-step explanation:
Given the expression
(3x-2)/(x+3)-1=(3x-3)/(x+1)-2
This can also be expressed as;
(3x-2)/x+2 = 3x-3/x-1
3x-2/x+2 = 3(x-1)/x-1
3x-2/x+2 = 3
Cross multiply
3x-2 = 3(x+2)
3x-2 =3x+6
Collect like terms
3x-3x =6+3
0x = 9
x = 9/0
x = infinity
Hence the expression had no solution. It tends to infinity