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2 years ago

Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:

1 answer:

8 0

<span>1) Use the balanced chemical equation to find the molar ratios (proportions) of each product and reactant.

3N2H4(l)→4NH3(g)+N2(g)

=> molar ratios: 3 mol N2H4 : 4 mol NH3

2) Use the product to reactant molar ratio, and the quantity of reactant to determine the yield:

2.0 mol N2H4 * [4mol NH3] / [3mol N2H4] = 2*4/3 mol NH3 = 2.7 mol NH3

Answer: 2.7 mol

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2. Which of the following is true about the total number of reactants and the total number of

Soloha48 [4]

9 moles of reactants chemically change into 11 moles of product.

Explanation:

In the reaction above, 9 moles of reactants chemically change into 11 mole of products. The coefficients in a reaction is the number of moles of the reacting atoms .

For example 8O₂ depicts 8 moles of two oxygen atoms.
The number of moles is a unit for quantifying particles.
You can liken it to a dozen, gross or a score.
Since a mole of a substance contains avogadro number of particles. We can relate the number of moles to other parameters.

Learn more:

Moles brainly.com/question/2272966

#learnwithBrainly

8 0

2 years ago

Read 2 more answers

Flourine is found to undergo 10% radioactivity decay in 366 minutes determine its halflife

yuradex [85]

Answer:

$\boxed{\text{2408 min}}$

Explanation:

The integrated rate law for radioactive decay is

$\ln\dfrac{N_{0}}{N_{t}} = kt$

1. Calculate the decay constant

$\begin{array}{rcl}\ln \dfrac{100}{90} & = & k \times 366\\\\1.054 & = & 366k\\\\k & = & \dfrac{1.054 }{366}\\\\k & = & 2.879 \times 10^{-4} \text{ min}^{-1}\\\end{array}\\\\$

2. Calculate the half-life

$t_{\frac{1}{2}} = \dfrac{\ln2}{k}\\\\t_{\frac{1}{2}} = \dfrac{\ln2}{2.879 \times 10^{-4} \text{ min}^{-1}} = \text{2408 min}\\\\\text{The half-life for decay is } \boxed{\textbf{2408 min}}$

8 0

2 years ago

In Universe , recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, quant

tiny-mole [99]

Answer:

Check the explanation

Explanation:

When talking about our universe there are 5 d orbitals. The element of first transition series moves away from the universal principles of Hund's rule and Aufbav's principle. So in order to attain stability these elements tend to form half or full filled orbitals.

In our universe the ground state electronic configuration of sixth transition metal, Iron (Fe) : [Ar] $3d^{6} 4s^{2}$

and the electronic configuration of seventh transition metal, Cobalt (Co) : [Ar] $3d^{7} 4s^{2}$

=================================

In universe L there are seven orbitals.

Ground state electronic configuration of sixth and seven transition element.

Sixth transition metal: [Ar] $3d^{7} 4s^1 or [X] 3d^{7} 4s^1$

Seventh transition metal: [Ar] $3d^{7} 4s^{2}or [X] 3d^{7} 4s^{2}$

7 0

2 years ago

Lavoisier made an important contribution to chemistry by _____.

Harlamova29_29 [7]

Answer:

Lavoisier made an important contribution to chemistry by the law of conservation of mass

Explanation:

The law of conservation of mass tell us, that the mass doens't change in a system. You have the same mass at the begining and in the end of a reaction.

Matter is neither created, nor destroyed in a chemical reaction.

This law also states that mass of reactants is the same of products in any chemical reaction

6 0

2 years ago

Copper chloride bihydrate. What might this name tell you about the atoms in this compound

lozanna [386]

Answer : The atoms in this compound are Copper(Cu), Chlorine(Cl), Hydrogen(H), Oxygen(O).

Explanation :

The given compound is copper chloride bi-hydrate which is also called as copper (II) chloride dihydrate as it contains two water of crystallisation.

The formula of copper chloride bi-hydrate is $CuCl_2.2H_2O$ .

Therefore, there are 4 atoms in this compound and they are Copper(Cu), Chlorine(Cl), Hydrogen(H) and Oxygen(O).

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2 years ago