Correct question:
An elevator in a mine shaft is stopped at 25 feet below ground level. And then travels 28 feet downward. What equation can be written to find the final position in feet of the elevator in relations to ground level?
Answer:
-53 feets
Step-by-step explanation:
Initial stop point = 25 feets below ground level
Further distance traveled = 28 feets below ground level
Final position in feet = Initial stop point + further distance traveled
Note : distances or point traveled below ground level or downward is represented as negative.
Final position in feets = (-25)feets + (-28)feets
Final position in feets = - 53 feets
Answer:
Bottom right
Step-by-step explanation:
Each domain value can only have 1 range value.
Answer:
1.5 I'm pretty shure
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given
Required
Determine Y'
Y' can be solved by multiplying the scale factor by Y
i.e.
For, the x coordinates.
Where
For the y coordinates:
Where
Hence:
Answer:
the slope is 5
Step-by-step explanation:
y = 5 x – 3
This equation is in slope intercept form
y = mx+b where m is the slope and b is the y intercept
the slope is 5 and the y intercept is -3
