a,b,c is your answer light and sound are not considered matter and heat is energy created from matter and electricity is particles moving basically therefore electricity is matter hope this helps
Answer:
<em>The PE of the mass increased by 6,972.95 J</em>
Explanation:
<u>Gravitational Potential Energy</u>
It's the energy stored in an object because of its vertical position or height in a gravitational field.
It can be calculated with the equation:
U=m.g.h
Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or 9.8 m/s^2.
We are given the mass of m=16 slug raised by a height h=10 ft. Both units will be converted to SI standard:
1 slug = 14.59 Kg, thus
16 slug = 16*14.59 Kg=233.44 Kg
1 ft = 0.3048 m, thus:
10 ft = 10*0.3048 m = 3.048 m
Thus, the PE of the mass increased by:
U = 233.44 * 9.8 * 3.048 = 6,972.95 J
the PE of the mass increased by 6,972.95 J
<span>Leaves of plants absorb light from the sun.Leaves of plants also absorb the air that people breathe out, called carbon dioxide.Leaves of plants also absorb water. ...Leave</span><span>How Do Primary Producers Make Their Own Food? - Tech Alive</span><span>techalive.mtu.edu/meec/module10/Howarenutrientscycledinaschoolyardecology.htm</span>s of plants use light from the sun to turn the air people breathe out and water into glucose and oxygen. GOT IT FROM
Answer:
ee that the lens with the shortest focal length has a smaller object
Explanation:
For this exercise we use the constructor equation or Gaussian equation
where f is the focal length, p and q are the distance to the object and the image respectively.
Magnification a lens system is
m = = -
h ’= -\frac{h q}{p}
In the exercise give the value of the height of the object h = 0.50cm and the position of the object p =∞
Let's calculate the distance to the image for each lens
f = 6.0 cm
as they indicate that the light fills the entire lens, this indicates that the object is at infinity, remember that the light of the laser rays is almost parallel, therefore p = inf
q = f = 6.0 cm
for the lens of f = 12.0 cm q = 12.0 cn
to find the size of the image we use
h ’= h q / p
where p has a high value and is the same for all systems
h ’= h / p q
Thus
f = 6 cm h ’= fo 6 cm
f = 12 cm h ’= fo 12 cm
therefore we see that the lens with the shortest focal length has a smaller object
Answer:
Explanation:
For fundamental frequency in a vibrating string , the formula is
n = 1 / 2L x √ ( T /m₁ )
n is frequency , L is length , T is tension and m₁ is mass per unit length .
For first string ,
293 = 1 / 2L x √ ( 49 N /m₁ )
For second string , let mass per unit length be m₂ .
196 = 1 / 2L x √ ( 49 N /m₂ ) ------ ( 1 )
To bring its frequency back to previous one let tension be T
293 = 1 / 2L x √ ( T /m₂ ) ------- ( 2 )
Dividing
293 / 196 = √ ( T /49 )
1.4948 = √ ( T /49 )
2.2344 = T /49
T = 109.48 N .