Answer:
Three hydrogen atoms to form PH₃.
Explanation:
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In this case, since the elements belonging to the nitrogen family (N, P, As, Sb and Bi) show five valence electrons, because there are five electrons at their outer shell, it is clear that if phosphorous bonds with hydrogen, it is going to require the same amount of oxygen atoms (3) because elements having five valence electrons need 3 bonds in order to attain the octet (5+3=8).
Therefore the compound would be:
Which is phosphine.
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Answer:
Explanation:
Hello!
In this case, as we know the mass of the total sample, we can first compute the mass of oxygen:
Next, we compute the moles of each element:
Now, we divide the moles by 0.184 moles, the fewest ones, to obtain:
Therefore, the empirical formula is:
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The nomenclature of binary covalent compounds follows these rules: The first element in the formula is given first, using the element's full name.
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Binary molecular (covalent) compounds.
compound systematic name common name
NO nitrogen monoxide nitric oxide
NO2 nitrogen dioxide
N2O3 dinitrogen trioxide
N2O4 dinitrogen tetroxide
Answer:
E
Explanation:
To know what will happen, we need to know
the total number of electrons the element have.
This can be calculated by adding all the electrons together
That would be 2 + 2 + 6 + 2 + 4 = 16
This shows that the element is sulphur.
Now using the KLMN electronic configuration, sulphur has the shells 2,8,6 meaning there are 2 extra electrons needed for octet configuration to be achieved.
This makes option E the correct answer to the question
