Answer:
90
Step-by-step explanation:
Evaluate x^2 + 2 x^2 + 3 x^2 + 4 x^2 where x = 3:
x^2 + 2 x^2 + 3 x^2 + 4 x^2 = 3^2 + 2×3^2 + 3×3^2 + 4×3^2
3^2 = 9:
3^2 + 2×9 + 3×3^2 + 4×3^2
3^2 = 9:
3^2 + 2×9 + 3×9 + 4×3^2
3^2 = 9:
3^2 + 2×9 + 3×9 + 4×9
3^2 = 9:
9 + 2×9 + 3×9 + 4×9
2×9 = 18:
9 + 18 + 3×9 + 4×9
3×9 = 27:
9 + 18 + 27 + 4×9
4×9 = 36:
9 + 18 + 27 + 36
| 3 |
| 3 | 6
| 2 | 7
| 1 | 8
+ | | 9
| 9 | 0:
Answer: 90
Solution :
Given
Let the initial approximation is
So by Newton's method, we get
are identical up to eight decimal places.
The approximate real root is x ≈ 1.32471795
∴ x = 1.32471795
We need the following to be true
a+2b = -a
a+4 = 2a - 3b
Let's look at the first equation.
a + 2b = -a
Subtract both sides by a
2b = -2a
b = -a
Substitute b= -a into the second equation
a+4 = 2a + 3a
a + 4 = 5a
4a = 4
a = 1
Just take the negative of that and you get the value of b.
b = -1
Your solution is a=1 and b = -1.
Have an awesome day! :)
T= MN+R
I believe that this is the right answer