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3 years ago

Find the measure of angle x in the figure below: 35° 47° 73° 78°

Mathematics

2 answers:

Rama09 [41]3 years ago

8 0

Answer:

i belive it is 35

Step-by-step explanation:

r-ruslan [8.4K]3 years ago

4 0

The answer is 35 if im right

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Please solve for M<PRQ

MakcuM [25]

Answer:

$m\angle PRQ =49\degree$

Step-by-step explanation:

$m\angle PSQ = 360\degree - (128\degree + 134\degree )$

$m\angle PSQ = 360\degree - 262\degree$

$m\angle PSQ = 98\degree$

Now, by inscribed angle theorem:

$m\angle PRQ = \frac{1}{2} \times m\angle PSQ$

$m\angle PRQ = \frac{1}{2} \times 98\degree$

$m\angle PRQ =49\degree$

5 0

2 years ago

HELP HELP <br> FIND THE VOLUME OF THE COMPOSITE SOLId

Y_Kistochka [10]

First of all,find the volume of prism by using the formulae V=1/3Ah.Then,find the volume of cuboid by using length × breadth × height.After that,you can find the answer. The answer is a.

7 0

2 years ago

Solve the following using Substitution method<br> 2x – 5y = -13<br><br> 3x + 4y = 15

Digiron [165]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\left. \begin{array} { l } { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.$

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

$2x-5y=-13, \: 3x+4y=15$

Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

$2x-5y=-13$

Add 5y to both sides of the equation.

$2x=5y-13$

Divide both sides by 2.

$x=\frac{1}{2}\left(5y-13\right) \\$

Multiply $\frac{1}{2}\\$ times 5y - 13.

$x=\frac{5}{2}y-\frac{13}{2} \\$

Substitute $\frac{5y-13}{2}\\$ for x in the other equation, 3x + 4y = 15.

$3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15 \\$

Multiply 3 times $\frac{5y-13}{2}\\$ .

$\frac{15}{2}y-\frac{39}{2}+4y=15 \\$

Add $\frac{15y}{2} \\$ to 4y.

$\frac{23}{2}y-\frac{39}{2}=15 \\$

Add $\frac{39}{2}\\$ to both sides of the equation.

$\frac{23}{2}y=\frac{69}{2} \\$

Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

$\large \underline{ \underline{ \sf \: y=3 }}$

Substitute 3 for y in $x=\frac{5}{2}y-\frac{13}{2}\\$ . Because the resulting equation contains only one variable, you can solve for x directly.

$x=\frac{5}{2}\times 3-\frac{13}{2} \\$

Multiply 5/2 times 3.

$x=\frac{15-13}{2} \\$

Add $-\frac{13}{2}\\$ to $\frac{15}{2}\\$ by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.