A +0.2 µC charge is in an electric field. What happens if that charge is replaced by a +0.4 µC charge?
1 answer:
Explanation:
It is known that electric field is responsible for creating electric potential. As a result, it depends only on the electric field and not on the magnitude of charge.
So, when a charge is increased by a factor of 2 then electric potential will remain the same. Since, expression to calculate the electric potential is as follows.
U = qV
Since, the electric potential is directly proportional to the charge. Hence, when 0.2 tends to replaced by 0.4
then charge is increased by a factor of 2. Hence, the electric potential energy is doubled.
Thus, we can conclude that if that charge is replaced by a +0.4 µC charge then electric potential stays the same, but the electric potential energy doubles.
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Answer:
The force will be "5,488". A further solution is provided below.
Explanation:
The given values are:
speed,
v = 100m/s
mass,
m = 80 kg
acceleration,
a = 7
Now,
Radius will be:
⇒
⇒
⇒
⇒
Force will be:
⇒
⇒
⇒
To solve the problem it is necessary to apply the concepts given in the kinematic equations of angular motion that include force, acceleration and work.
Torque in a body is defined as,
And in angular movement like
Where,
F= Force
d= Distance
I = Inertia
Acceleration Angular
PART A) For the given case we have the torque we have it in component mode, so the component in the X axis is the net for the calculation.
On the other hand we have the speed data expressed in RPM, as well
Acceleration can be calculated by
In the case of Inertia we know that it is equivalent to
Matching the two types of torque we have to,
PART B) The work performed would be calculated from the relationship between angular velocity and moment of inertia, that is,