Answer:
Explanation:
Hello,
In this case, by considering the mathematical definition of by mass percentage of a solute as shown below:
We are able to compute the mass of the solute in a 20% solution having 500 g of solution as follows:
Best regards.
<span>C7H16 + 11 O2 = 7 CO2 + 8 H2O
If you write it like this then it is balanced.</span>
Answer:
copper(I) bromide: CuBr
copper(I) oxide: Cu₂O
copper(II) bromide: CuBr₂
copper(II) oxide: CuO
iron(III) bromide: FeBr₃
iron(III) oxide: Fe₂O₃
lead(IV) bromide: PbBr₄
lead(IV) oxide: PbO₂
I hope this helped you! Brainliest would be greatly appreciated.
1kg of water has greater internal energy compared to 1g of water because 1kg of water has more mass.
Answer:
1. 2NaN₃(s) → 2Na(s) + 3N₂(g)
2. 14.5 g NaN₃
Explanation:
The answer is incomplete, as it is missing the required values to solve the problem. An internet search shows me these values for this question. Keep in mind that if your values are different your result will be different as well, but the solving methodology won't change.
" The airbags that protect people in car crashes are inflated by the extremely rapid decomposition of sodium azide, which produces large volumes of nitrogen gas. 1. Write a balanced chemical equation, including physical state symbols, for the decomposition of solid sodium azide (NaN₃) into solid sodium and gaseous dinitrogen. 2. Suppose 71.0 L of dinitrogen gas are produced by this reaction, at a temperature of 16.0 °C and pressure of exactly 1 atm. Calculate the mass of sodium azide that must have reacted. Round your answer to 3 significant digits. "
1. The <u>reaction that takes place is</u>:
- 2NaN₃(s) → 2Na(s) + 3N₂(g)
2. We use PV=nRT to <u>calculate the moles of N₂ that were produced</u>.
P = 1 atm
V = 71.0 L
n = ?
T = 16.0 °C ⇒ 16.0 + 273.16 = 289.16 K
- 1 atm * 71.0 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 289.16 K
Now we <u>convert N₂ moles to NaN₃ moles</u>:
- 0.334 mol N₂ * = 0.223 mol NaN₃
Finally we <u>convert NaN₃ moles to grams</u>, using its molar mass:
- 0.223 mol NaN₃ * 65 g/mol = 14.5 g NaN₃