Answer:
<em>x = 0.05</em>
<em>x = 1.57</em>
Step-by-step explanation:
The given equation is:
Moving all terms to the left side:
Now we define a function:
The solutions of the equation are the values of x such that y=0.
Since the function cannot be solved by algebraic methods, we use a graphing tool.
Those points where the graph crosses the x-axis are solutions of the equation.
Please refer to the graph in the figure below.
We can clearly identify there are two solutions at
x = 0.05
x = 1.57
|x| = x for x ≥ 0
examples:
|3| = 3; |0.56| = 0.56; |102| = 102
|x| = -x for x < 0
examples:
|-3| = -(-3) = 3; |-0.56| = -(-0.56) = 0.56; |-102| = 102
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Use PEMDAS:
P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
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Put the values of x to the equation of the function h(x):
g(x) = (1/4)x^2 . correct option C) .
<u>Step-by-step explanation:</u>
Here we have , and we need to find g(x) from the graph . Let's find out:
We have , . From the graph we can see that g(x) is passing through point (2,1 ) . Let's substitute this point in all of the four options !
A . g(x) = (1/4x)^2
Putting (2,1) in equation g(x) = (x/4)^2 , we get :
⇒
⇒
Hence , wrong equation !
B . g(x) = 4x^2
Putting (2,1) in equation g(x) = 4x^2 , we get :
⇒
⇒
Hence , wrong equation !
C . g(x) = (1/4)x^2
Putting (2,1) in equation g(x) = (1/4)x^2 , we get :
⇒
⇒
Hence , right equation !
D . g(x) = (1/2)x^2
Putting (2,1) in equation g(x) = (1/2)x^2 , we get :
⇒
⇒
Hence , wrong equation !
Therefore , g(x) = (1/4)x^2 . correct option C) .
1: -17 + 15 = -2 P = -17
2: 8 x -8 = -64 y = -8
3: -2 x 6 = -12
4: 8 - (-4) = 12
Hope I Helped
Im pretty sure the quotient is 92