We need to know wat it looks like
thats all right but part 3 of 3 is 7.5
Start at 5 on x line, then go 3 up one over and that’s how you find it
Answer:
Step-by-step explanation:
Given that acceleration of an object is
is the solution to the differential equation
Since v(0) =7
we get ln 7 = C
Hence 
since velocity is rate of change of distance s we have
![v=\frac{ds}{dt} =7e^{-2t}\\s= [tex]s(t) =\frac{-7}{2} (e^{-2t})+C)[](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bds%7D%7Bdt%7D%20%3D7e%5E%7B-2t%7D%5C%5Cs%3D%20%5Btex%5Ds%28t%29%20%3D%5Cfrac%7B-7%7D%7B2%7D%20%28e%5E%7B-2t%7D%29%2BC%29%5B)
substitute t=0 and s=0
So solution for distance is
For quite some time now, calculators have had statistical functions built in. Here we need to use the stat. function normalcdf, which has only two inputs when we're working with z scores instead of raw scores.
Here,
normalcdf(-100,1.25) = 0.894
This same result could be obtained using a table of z-scores.
