Explanation:
Given that,
Fapp = 67.0 N at 30.0° above the horizontal (rightward and upward)
Fnorm = 64.5 N, up
Ffrict = 27.6 N, left
Fgrav = 98 N, down
(a) Resolution of the applied force:
Horizontal component,
Vertical component,
(b) Net horizontal force :
It is positive, it will act in right side
Net vertical force :
Hence, it is clear that the net force is in horizontal direction i.e. 30.42 N due right side.
Blank is something empty lol
Answer:
K = 36 J
Explanation:
In this exercise we must use the conservation of mechanical energy at two points at initial x = 0 and the end point of maximum compression of the spring
Initial x = 0
Em₀ = K = ½ m v²
Final point of maximum compression
= Ke = ½ k x²
Em₀ =
K = ½ k x²
We put the kinetic energy because it is a data, let's look for the spring constant
k = 2 K / x²
k = 2 9 / d²
k = 18 / d²
Let's calculate the kinetic energy, so that the compression is x = 2d
K = ½ k x²
K = ½ (18 / d²) (2d)²
K = ½ 18/d² 4d²
K = 36 J
Answer:
Speed acquired (Final velocity) = 12 m/s
Distance travelled = 720 meter
Explanation:
Given:
Uniform acceleration = 0.1 m/s²
Initial velocity = 0 m/s
Time taken = 2 minutes = 2 x 60 = 120 second
Find:
(a) Speed acquired (Final velocity)
(b) Distance travelled
Computation:
v = u + at
v = 0 + 0.1(120)
Speed acquired (Final velocity) = 12 m/s
Distance travelled = ut + (1/2)(a)(t²)
Distance travelled = (0)(120) + (1/2)(0.1)(120²)
Distance travelled = (1/2)(0.1)(14400)
Distance travelled = 720 meter
B. Density. I hope this helps!