Answer:
the numbers who's difference is 16 and the product is 720 is
36 &20
Explanation:
to finding numbers you have to express the equation in a quadratic equation then Factor it.
since the two numbers have a difference of 16 you can say that the first number is x and the second number is x -16 then their product is 720.
x(x-16)=720
x²-16x=720
x²-16x-720=0
(x-36)(x+20)
there are two possible value of x but since you are looking for the positive value of x, choose the positive value of x the first number is 20.
To find the second number
x-16=20
x=20+16
x=36
the second number is 36
<u>Now </u><u>to </u><u>check</u>
<u>3</u><u>6</u><u>-</u><u>2</u><u>0</u><u>=</u><u>1</u><u>6</u>
<u>2</u><u>0</u><u>*</u><u>3</u><u>6</u><u>=</u><u>7</u><u>2</u><u>0</u>
For this case we have the following system of equations:
We multiply the second equation by -5:
Now we add the equations:
We find the value of the variable "y":
THE solution is: (-6, -3)
Answer:
(-6, -3)
As 1/3 = 2/6 = 3/9 = 4/12
and 2/6 is greater than 1/6
3/9 is greater than 2/9
etc..
So
1/3 is greater than 1/6 ; 2/9 ; ...
Answer:
x = 4
, y = 6
Step-by-step explanation:
Solve the following system:
{x + 3 y = 22 | (equation 1)
2 x - y = 2 | (equation 2)
Swap equation 1 with equation 2:
{2 x - y = 2 | (equation 1)
x + 3 y = 22 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{2 x - y = 2 | (equation 1)
0 x+(7 y)/2 = 21 | (equation 2)
Multiply equation 2 by 2/7:
{2 x - y = 2 | (equation 1)
0 x+y = 6 | (equation 2)
Add equation 2 to equation 1:
{2 x+0 y = 8 | (equation 1)
0 x+y = 6 | (equation 2)
Divide equation 1 by 2:
{x+0 y = 4 | (equation 1)
0 x+y = 6 | (equation 2)
Collect results:
Answer: {x = 4
, y = 6