Answer:
To spend at most $93, they need to rent the room less than or equal 13 hours.
Step-by-step explanation:
<u><em>The complete question is</em></u>
To rent a certain meeting room, a college charges a reservation fee of $15 and an additional fee of $6 per hour. The chemistry club wants to spend at most $93 on renting a room. What are the possible numbers of hours the chemistry club could rent the meeting room? Use t for the number of hours. Write your answer as an inequality solved for t,
Let
t ----> the number of hours
we know that
I this problem the word "at most" means "less than or equal to"
The number of hours rented multiplied by the cost per hour, plus the reservation fee, must be less than or equal to $93
so
The inequality that represent this situation is
solve for t
subtract 15 both sides
Divide by 6 both sides
therefore
To spend at most $93, they need to rent the room less than or equal 13 hours.
The graphs are curved, not segments ending in a point.
http://www.wolframalpha.com/input/?i=plot+y+%3D+sin+x+for+-3.2+%3C+x+%3C+3.2+and+-1.1+%3C+y+%3C+1.2
The value of the the car is given by:
V=L(1-d.n)
thus, the value of v when L=$21000 and d.n=0.7 will be:
V=21000(1-0.7)
V=21000×0.3
V=$6300
Answer: Present value of the car is $6300
I think it going to be 21/2 or 10 1/2
Answer:
Step-by-step explanation:
He has $500 to start with, and he takes $25 out of the account each week. But he wants more than 200 in his account by the end of summer. 25 goes into 500 20 times. But if he wanted more than 200 left, like 300-400, he could spend 4 week's worth of money to have 400 left, or 8 weeks to have 300 left. This is the best-case scenario.