Answer:
<h2>Hyy There !! </h2>
Step-by-step explanation:
<h3><u>Question Says :- </u></h3>
• The Area of a sector when r = 9/2 and
θ = 5pi/6 radians ? .
? pi / ?
<h3><u>Circular Area of a Sector</u></h3>
Problems involving area of a sector can be solved easily. One should just obtain two essential information from the circle of interest, the central angle measure θ and radius r For angle measures in radians, the area A is calculated as :-
<h3>A = 1/2r^2θ. </h3>
<h3>Hope this helps you !! </h3>
Answer:
Step-by-step explanation:
-6x²+15x+9=0
divide by -3
2x²-5x-3=0
2x²+x-6x-3=0
x(2x+1)-3(2x+1)=0
(2x+1)(x-3)=0
either x=-1/2
or x=3
Dino nuggets
Bro stop scrolling
Please fix the equation in the second part. Is it + or -.
Answer:
4:3
Step-by-step explanation:
You divide 8 and 6 by 2 to simplify it
