<span>Let n be the number of taxis in NY. The average distance travelled is 60,000 miles, therefore the middle 95% will have the same average as the population, the reason being the mileage is symmetrically distributed about the mean Therefore the total number of miles in one year for the middle 95% is 60,000 * 0.95 * n
</span><span>The range of miles driven by the middle 95% can be found from the empirical rule that says:
For a normal distribution, approximately 95% of the data points lie within the range plus and minus 2 standard deviations of the population mean. In this case the range is
(60,000-22,000) to (60,000 + 22,000)</span>
Answer:
Total ways = 5×5×5×5×5
Total ways = 5^5
Total ways = 3125
Therefore, the correct option is C) 5^5
Step-by-step explanation:
John has pairs of red, orange, yellow, blue and green socks.
Which means that John has 5 different colors pairs of socks.
We are asked to find out in how many ways can he wear them over 5 days.
1st Day:
On the first day John has 5 ways to choose from.
2nd Day:
On the second day John has 5×5 ways to choose from.
(Since repetition is allowed)
3rd Day:
On the third day John has 5×5×5 ways to choose from.
4th Day:
On the fourth day John has 5×5×5×5 ways to choose from.
5th Day:
On the fifth day John has 5×5×5×5×5 ways to choose from.
Total ways = 5×5×5×5×5
Total ways = 5^5
Total ways = 3125
Therefore, the correct option is C) 5^5
<BOA = 360 -250 = 110
<<span>BDA = 110/2 = 55
<</span><span>BCA = 360 - (90+90+110)
</span><<span>BCA = 360 - 290
<</span><span>BCA = 70</span>
Answer:
2) x = 6 y = 7 3) x = -5 y= 2
Step-by-step explanation:
2) 10x - 8y = 4
2(-5x + 3y = -9)
-10x + 6y = -18
10x - 8y = 4 Add both equations together
-2y = -14
y = 7 Divide both sides by -2
10(x) - 8(7) = 4 Plug in 7 for the y to solve for x
10x - 56 = 4
+ 56 + 56 Add 56 to both sides
10x = 60
x = 6 Divide both sides by 10
3) Where the two lines intersect, that is the solution to x and y.
The lines intersect at (-5,2). x = -5 y = 2
HMMMMMMM...It could be C...
An Arc is the the end of the circle, the OUTER rim..do you get what I'm trying to say? SO, if you look at AC, it looks like an arc.
Hope this helps!
