C^2 + 11c = 12
c^2 + 2[11/2] c = 12
[c + 11/2] ^2 - [11/2]^2 = 12
[c +11/2]^2 = 12 +[11/2]^2
[c +11/2]^2 = 12 + 121/4
[c +11/2]^2 =[48+121]/4
[c +11/2]^2 = 169/4 ----> This is the resulting equation
Solving it you get:
c + 11/2 = +/- √(169/4)
c + 11/2 = +/- 13/2
c = 13/2 - 11/2 =2/2 = 1 and
c = -13/2 - 11/2 = - 24/2 = -12
Answer:
sin
(
x/
2
) = -
√
3
/2
Take the inverse sine of both sides of the equation to extract x
from inside the sine.
x/
2
=
arcsin
(
−
√
3/
2
)
The exact value of arcsin
(
−
√
3
/2
) is −
π
/3
.
/x
2
=
−
π
/3
Multiply both sides of the equation by 2
.
2
⋅
x
/2
=
2
⋅
(
−
π
/3
)
Simplify both sides of the equation.
x
=
−
2
π
/3
The sine function is negative in the third and fourth quadrants. To find the second solution, subtract the solution from 2
π
, to find a reference angle. Next, add this reference angle to π to find the solution in the third quadrant.
x
/2
=
2
π
+
π/
3
+
π
Simplify the expression to find the second solution.
x
=
2
π
/3
4
π
Add 4
π to every negative angle to get positive angles.
x
=
10
π
/3
The period of the sin
(
x
/2
) function is 4
π so values will repeat every 4
π radians in both directions.
x
=2
π
/3
+
4
π
n
,
10
π/
3
+
4
π
n
, for any integer n
Exclude the solutions that do not make sin
(
x
/2
)
=
−
√
3/
2 true.
x
=
10
π
/3
+
4
π
n
, for any integer n
A. = 7/8
b. = 7/4 = 1 3/4
c. = 7/4 = 1 3/4
d. = 7/4 = 1 3/4
= b,c,d
Answer:
The = sign
Step-by-step explanation:
1 11/20 = 31/20 = 1.55 and 1.55 =1.55
We need to find the value of the hypotenuse in order to solve this problem.
12^2+4^2=H^2
Therefore:
H=√(144+16)
H=4√10
Now:
sin(G)=O/H=4/(4√10)
=1/(√10)
=(√10)/10