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2 years ago

Please help need answers asap

Physics

1 answer:

Soloha48 [4]2 years ago

4 0

Answer- Helium
You can by the number of protons, and if you look at a periodic table the atomic number of helium is the same as the number of protons

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What is the relation between Physical states of solution and solvent

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Explanation:

The solute does not have to be in the same physical state as the solvent, but the physical state of the solvent usually determines the state of the solution. As long as the solute and solvent combine to give a homogeneous solution, the solute is said to be soluble in the solvent.

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2 years ago

Go outside on a clear night, wait 15 minutes for your eyes to adjust to the dark, and look carefully at the brightest stars. Som

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Answer:

blue star is hotter than red

Explanation:

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Blue coloured star is hotter than red coloured star.

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2 years ago

You are standing at the top of a cliff that has a stairstep configuration. There is a vertical drop of 6 m at your feet, then a

Zigmanuir [339]

Answer:

4.5 m/s

Explanation:

The rock must barely clear the shelf below, this means that the horizontal distance covered must be

$d_x = 5 m$

while the vertical distance covered must be

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The rock is thrown horizontally with velocity $v_x$ , so we can rewrite the horizontal distance as

$d_x = v_x t$

where t is the time of flight. Re-arranging the equation,

$t=\frac{d_x}{v_x}$ (1)

The vertical distance covered instead is

$d_y = \frac{1}{2}gt^2$

where we omit the term $ut$ since the initial vertical velocity is zero. From this equation,

$t=\sqrt{\frac{2d_y}{g}}$ (2)

Equating (1) and (2), we can solve the equation to find $v_x$ :

$\frac{d_x}{v_x}=\sqrt{\frac{2d_y}{g}}\\\frac{d_x^2}{v_x^2}=\frac{2d_y}{g}\\v_x = d_x \sqrt{\frac{g}{2d_y}}=5\sqrt{\frac{9.8}{2(6)}}=4.5 m/s$

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2 years ago

What is the process by which engine fuels burn

BigorU [14]

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2 years ago

Read 2 more answers

A truck is traveling at 27 m/s down the interstate highway where you are changing a flat tire. frequency of 185 Hz.

Reil [10]

Answer:

(a) the observed frequency is 200 Hz

(b) the observed frequency is 188 Hz.

Explanation:

speed of the truck, Vs = 27 m/s

frequency of the truck as it approaches, Fs = 185 Hz

(a) Apply Doppler effect to determine the frequency you will hear.

As the truck approaches you, the observed frequency will be higher than the source frequency because of decrease in distance.

$F_s = F_o [\frac{V}{V_S + V} ]$

Where;

Fo is the observed frequency which is the frequency you will hear.

V is speed of sound in air

$F_s = F_o [\frac{V}{V_S + V} ]\\\\185 = F_o [\frac{340}{27 + 340} ]\\\\185 = F_o (0.926)\\\\F_o = \frac{185}{0.926}\\\\F_o = 199.78 \ Hz$

$F_o = 200 \ Hz$

(b) Apply the following formula for a moving observer and a moving source;

$F_o = F_s[\frac{V-V_o}{V} ](\frac{V}{V-V_S} )$

The observed frequency is negative since you are driving away from the truck and the source frequency is also negative since it is driving towards you.

$F_o = F_s[\frac{V-V_o}{V} ](\frac{V}{V-V_S} )\\\\F_o = 185[\frac{340-22}{340} ](\frac{340}{340-27} )\\\\F_o = 185(0.9353)(1.0863)\\\\F_o = 188 \ Hz$

5 0

2 years ago

Please help need answers asap ​

Please help need answers asap