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2 years ago

9

What is 497÷2 (Use long division on a piece of paper) Explain how you figured this out clearly so I can play along because I won

't be solving it with you. Hope this helps you!!

1 answer:

erma4kov [3.2K]2 years ago

8 0

Dividing 2 into 4 you would get 2 and dividing it into 9 you would get 4 since you can't divide it into 9 so when you subtract that (9-8) you would get 1 you place a decimal and bring down a zero to get 10 then you would get 5 the answer would be 248.5

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Evaluate c (y + 7 sin(x)) dx + (z2 + 9 cos(y)) dy + x3 dz where c is the curve r(t) = sin(t), cos(t), sin(2t) , 0 ≤ t ≤ 2π. (hin

saw5 [17]

Treat $\mathcal C$ as the boundary of the region $\mathcal S$ , where $\mathcal S$ is the part of the surface $z=2xy$ bounded by $\mathcal C$ . We write

$\displaystyle\int_{\mathcal C}(y+7\sin x)\,\mathrm dx+(z^2+9\cos y)\,\mathrm dy+x^3\,\mathrm dz=\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r$

with $\mathbf f=(y+7\sin x,z^2+9\cos y,x^3)$ .

By Stoke's theorem, the line integral is equivalent to the surface integral over $\mathcal S$ of the curl of $\mathbf f$ . We have

$\nabla\times\mathbf f=(-2z,-3x^2,-1)$

so the line integral is equivalent to

$\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\mathrm d\mathbf S$
$=\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv$

where $\mathbf s(u,v)$ is a vector-valued function that parameterizes $\mathcal S$ . In this case, we can take

$\mathbf s(u,v)=(u\cos v,u\sin v,2u^2\cos v\sin v)=(u\cos v,u\sin v,u^2\sin2v)$

with $0\le u\le1$ and $0\le v\le2\pi$ . Then

$\mathrm d\mathbf S=\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv=(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv$

and the integral becomes

$\displaystyle\iint_{\mathcal S}(-2u^2\sin2v,-3u^2\cos^2v,-1)\cdot(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv$
$=\displaystyle\int_{v=0}^{v=2\pi}\int_{u=0}^{u=1}u-6u^4\sin^3v-4u^4\cos v\sin2v\,\mathrm du\,\mathrm dv=\pi$ <span />

4 0

2 years ago

1) Bob weighed 200 lbs, but after dieting for 6 months, he weighed 170 lbs.

aivan3 [116]

Answer: 15%

Step-by-step explanation:

The Percentage decrease will be:

= Decrease in weight / Old weight × 100

= (200 - 170) / 200 × 100

= 30/200 × 100

= 15%

The Percentage decrease is 15%

7 0

2 years ago

Chen wants to buy a pair of pants that regularly cost $54 . Today, the pants are on sale for 60% of the original price.

s2008m [1.1K]

Do a proportion
60/100= x/54

Cross multiply and divide
54 x 60= 3,240
3,240 divided by 100 is 32.4

Now subtract
54- 32.4= 21.6
Answer is $21.6

3 0

2 years ago

11t - 6t = 45 solve the equation and enter the value of t below

Arada [10]

Answer:

$t = 9$

Step-by-step explanation:

$11t - 6t = 45$

$5t = 45$

<h3> $t = \frac{45}{5}$ </h3>

$t = 9$

<h3>Hope it is helpful....</h3>

8 0

2 years ago

Read 2 more answers

Pls help meh...... with the question.....pls it's urgent ...........

HACTEHA [7]

Answer:

1.6962 = 1.70 (2 dp)

0.4247 = 0.425 to 3 dp

0.007395 = 0.007 to 3 dp

0.007395 = 0.0074 to 4 dp

32549 = 32500 to 3 significant figures

32549 = 32550 to 4 significant figures

909520 = 910000 to 3 significant figures

909520 = 909500 to 4 significant figures

Step-by-step explanation:

1.6962 = 1.70 (2 dp)

0.4247 = 0.425 to 3 dp

0.007395 = 0.007 to 3 dp

0.007395 = 0.0074 to 4 dp

32549 = 32500 to 3 significant figures

32549 = 32550 to 4 significant figures

909520 = 910000 to 3 significant figures

909520 = 909500 to 4 significant figures

5 0

2 years ago