All categories

2 years ago

When naming a binary compound, what ending do you use to represent anions?

1 answer:

6 0

I believe You replace the ending of the elements name with -ide. example: magnesium flourine should should be magnesium flouride.

You might be interested in

How many molecules are contained in 125 grams of water, H20?

sergejj [24]

Answer:

18,01528

Explanation:

8 0

2 years ago

Read 2 more answers

A 13 g sample of P4010 contains how many

Alex777 [14]

Answer:

$\large \boxed{5.5 \times 10^{22}\text{ molecules of P$_{2}$O}_{5}}$

Explanation:

You must calculate the moles of P₄O₁₀, convert to moles of P₂O₅, then convert to molecules of P₂O₅.

1. Moles of P₄O₁₀

$\text{Moles of P$_{4}$O}_{10} = \text{13 g P$_{4}$O}_{10} \times \dfrac{\text{1 mol P$_{4}$O}_{10}}{\text{283.89 g P$_{4}$O}_{10}} = \text{0.0458 mol P$_{4}$O}_{10}$

2. Moles of P₂O₅

P₄O₁₀ ⟶ 2P₂O₅

The molar ratio is 2 mol P₂O₅:1 mol P₄O₁₀

$\text{Moles of P$_{2}$O}_{5} = \text{0.0458 mol P$_{4}$O}_{10} \times \dfrac{\text{2 mol P$_{2}$O}_{5}}{\text{1 mol P$_{4}$O}_{10}} = \text{0.0916 mol P$_{2}$O}_{5}$

3. Molecules of P₂O₅

$\text{No. of molecules} = \text{0.0916 mol P$_{2}$O}_{5} \times \dfrac{6.022 \times 10^{23}\text{ molecules P$_{2}$O}_{5}}{\text{1 mol P$_{2}$O}_{5}}\\\\= \mathbf{5.5 \times 10^{22}}\textbf{ molecules P$_{2}$O}_{5}\\\text{There are $\large \boxed{\mathbf{5.5 \times 10^{22}}\textbf{ molecules of P$_{2}$O}_{5}}$}$

6 0

2 years ago

How do liquids with high velocity differ from liquids with low velocity

Yanka [14]

Answer:

whah the other dude said :) also stay safe

Explanation:

5 0

2 years ago

HELPPPPPP is this 1:conduction 2:radiation 3:convection

qaws [65]

Answer:

Radiation

Explanation:

Sun rays shine on earth. Thats radiation.

3 0

2 years ago

How do you find the molar mass of a hydrate

Darya [45]

If you mean hydrate as in MgSO4 · 7H2O, then simply find the molar mass of each element you see.

For the example above, that means you would add the molar mass (found on the periodic table) of Mg, then S, then 4(O), 14(H), and 7(O).

The results would be your molar mass for the hydrate.

I hope this is what you meant by your question!

6 0

2 years ago