First, we need to work out the total number of students who were being surveyed.
We know that half of the students has two pets. The rest of the students make up the other half. So, we have 3 students + 2 students + 8 students = 13 students that make half of the sample population
That means total number of students being surveyed is 13+13=26 students
Then we work out the probability
P(One pet) = 8/26 = 4/13
P(Two pets) = 1/2
P(Three pets) = 3/26
P( Four pets) = 2/26 = 1/13
The probability distribution is shown in the table below. Let
be the number of pets and
is the probability of owning the number of pets
It it 270 degrees for the shaded part of it
Answer:
Point on Midline (0,3)
Maximum (9π/2,3)
Minimum (-9π/2,-3)
Step-by-step explanation:
in the given sine function which is in the form of f(x) = a sin(bx+c) +d
a = amplitude
period = frequency = 18π
Therefore b = 2π/18π = 1/9
Y intercept = vertical shift = 3
Horizontal shift = d = 0
Therefore the sine function will be
f(x) = 6 sin(x/9) + 3
Now first point on the midline is (0,3)
Second point is maximum (9π/2,9)
Third point be a minimum value ( -9π/2,-3)
Slope: (y2-y1)/(x2-x1)
(0,7) and (-4,7)
(7-7)/(-4-0) = 0/ -4
The slope is 0
14, 10, 2, 5, 8, 12, 12, 3, 2, 2, 13, 15, 6 Find the median
hoa [83]
Answer:
10
Step-by-step explanation: