70%
12+27+91 = 130
91/130 = .7
.7x100 = 70%
___
.700
7.00
70.0
Answer is 70%
4 tens = 40 and 5 tens = 50 … therefore the number has to be between 40 and 50
So: 40 < x <50 … this says that x is greater than 40 and less than 50
So the possible numbers would be: 41,42,43,44,45,46,47,48,49
Now the number must have 9 ones … which mean the only number would be 49
Answer:
Option (4)
Step-by-step explanation:
Given : XZ ≅ DF and ∠X ≅ ∠D
To prove : ΔXYZ ≅ ΔDEF
Statements Reasons
1). XZ ≅ DF 1). Given
2). ∠X ≅ ∠ D 2). Given
3). XY ≅ DE 3). Required information
4). ΔXYZ ≅ ΔDEF 4). By SAS property of congruence
Therefore, Option (4) will be the answer.
F(g(-2))=4(-2)^6+4(-2)^3+1
f(g(-2))=4(64)+4(-8)+1
f(g(-2))=256-32+1
f(g(-2))=224+1
f(g(-2))=225
4/7, because both the numerator and denominator can be divisible by 3.
