A rocket is launched from the top of a 99-foot cliff with an initial velocity of 122 ft/s. a. Substitute the values into the ver
1 answer:
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Answer:
Step-by-step explanation:
Box plot is enclosed.
To find out 5 number summary
3.0, 3.5, 4.5, 5.5, 6.5, 6.5, 7.0, 7.0, 7.0, 7.0, 7.0, 7.5, 8.0, 9.0, 9.0, 9.0, 9.5, 9.5, 9.5, 9.5}
Minimum: 3.0
Quartile Q1: 6.5
Median: 7
Quartile Q3: 9
Maximum: 9.5
Besides we find that
Average (mean): μ=7.25
Absolute deviation: 30.5
Mean deviation: 1.525
Minimum: 3.0
Maximum: 9.5
Variance: 3.7125
Standard deviation σ=1.926
Answer:
The rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.
Step-by-step explanation:
Given information:
A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station.
We need to find the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station.
According to Pythagoras
.... (1)
Put z=1 and y=2, to find the value of x.
Taking square root both sides.
Differentiate equation (1) with respect to t.
Divide both sides by 2.
Put , y=2,
in the above equation.
Divide both sides by 2.
Therefore the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.
