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2 years ago

What's 1.8499 x 10^9 in standard notation

Mathematics

1 answer:

maxonik [38]2 years ago

5 0

you just have to move the decimal point 9 places to the right thats an easy trick to remember 1849900000

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Your friend's swimming pool is in the shape of a rectangular prism, with a length of 25 feet, a width of 8 feet, and a height of

RUDIKE [14]

Answer:

Part a) $V=1,000\ ft^{3}$

Part b) $h=5\ ft$

Part c) $=718\ gal$

Step-by-step explanation:

Part a) What is the volume of your friend's swimming pool?

we know that

The volume of a rectangular prism is equal to

$V=LWH$

substitute the values

$V=(25)(8)(5)=1,000\ ft^{3}$

Part b) Your swimming pool is in the shape of a cylinder with a diameter of 16 feet and has the same volume as your friend's pool. What is the height of your pool?

we know that

The volume of a cylinder is equal to

$V=\pi r^{2} h$

we have

$V=1,000\ ft^{3}$

$r=16/2=8\ ft$ ----> the radius is half the diameter

substitute and solve for h

$1,000=\pi (8)^{2} h$

$h=1,000/(64 \pi)$

$h=1,000/(64*3.14)=5\ ft$

Part c) While you were on vacation, 6 inches of water evaporated from your pool. About how many gallons of water evaporated from your pool?

remember that

$1\ ft=12\ in$

$6\ in=6/12=0.5\ ft$

Find the volume of water for $h=5-0.5=4.5\ ft$

$V=(3.14)(8)^{2}(4.5)=904.32\ ft^{3}$

the volume of water evaporated is equal to

$1,000\ ft^{3}-904.32\ ft^{3}=95.68\ ft^{3}$

convert to gallons

remember that

$1\ ft^{3}=7.5\ gal$

$95.68\ ft^{3}=95.68*7.5=718\ gal$

5 0

2 years ago

Help help help help help help

kati45 [8]

Answer:

$6^{5}$

Step-by-step explanation:

I hope this helps

4 0

1 year ago

Read 2 more answers

I need you to answer with a, b, c, d

solong [7]

To find the zeros of a quadratic fiunction given the equation you can use the next quadratic formula after equal the function to 0:

$\begin{gathered} ax^2+bx+c=0 \\ \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}$

For the given function:

$f(x)=2x^2-10x-3$ $x=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(2)(-3)}}{2(2)}$ $x=\frac{10\pm\sqrt[]{100+24}}{4}$ $\begin{gathered} x=\frac{10\pm\sqrt[]{124}}{4} \\ \\ x=\frac{10\pm\sqrt[]{2\cdot2\cdot31}}{4} \\ \\ x=\frac{10\pm\sqrt[]{2^2\cdot31}}{4} \\ \\ x=\frac{10\pm2\sqrt[]{31}}{4} \\ \end{gathered}$ $\begin{gathered} x_1=\frac{10}{4}+\frac{2\sqrt[]{31}}{4} \\ \\ x_1=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \end{gathered}$ $\begin{gathered} x_2=\frac{10}{4}-\frac{2\sqrt[]{31}}{4} \\ \\ x_2=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}$

Then, the zeros of the given quadratic function are: