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2 years ago

Solve the linear system -x+2y=3 and 2x+y=4 by graphing

Mathematics

1 answer:

Scrat [10]2 years ago

4 0

Answer:

(x, y) = (1, 2)

Step-by-step explanation:

Given the features of graphing calculators these days, obtaining a solution by graphing is one of my favorite methods. The attached graph shows the solution to be (x, y) = (1, 2).

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Please help

vagabundo [1.1K]

I would say no to that.

4 0

2 years ago

Help me answer this please:)

Dmitrij [34]

Answer:

A and B

Step-by-step explanation:

$\frac{7x+6}{2}\leq 3x+2 < ==multiply\ both\ sides\ by\ 2\\2(\frac{7x+6}{2}\leq 3x+2)\\\\7x+6\leq6x+4 < ==subtract\ -6x\ from\ both\ sides\ \\-6x \ \ -6x\\\\x+6\leq4 < ==subtract\ 6\ from\ both\ sides\\-6 \ \ \ -6\\\\x\leq-2 < ==answer\ should\ be\ anything\ less\ than\ or\ equal\ to\ -2$

Now, look at your answer choices, which options are less than or equal to -2?

x ≤ -2, Check your answers:

A. -3 ≤ -2?

This statement is correct (-3 is < -2)

B. -2 ≤ -2 <== our original answer

This statement is correct (-2 is = to -2)

C. -1 ≤ -2

This statement is incorrect (-1 is > -2, not ≤ -2)

D. 0 ≤ -2

This statement is incorrect (0 is > -2, not ≤ -2)

E. 1 < -2

This statement is incorrect (1 is > -2, not ≤ -2)

Therefore, the correct options are A and B

Hope this helps!

6 0

1 year ago

What is the value of 128x3/7 as a whole number ?

UNO [17]

Answer:

54.86 or 55, rounded to a whole number

Step-by-step explanation:

(128*3) = 384

384/7 = 54.86

This is not a whole number

6 0

11 months ago

Consider the following functions. f(x) = x^2- 4 g(x) = x-2 What is (f(x)) (g(x))?

rodikova [14]

Answer:

(f(x) g(x)) = $x^3-2x^2-4x+8 ;$ all real numbers

Step-by-step explanation:

(f(x) g(x)) = $(x^{2} -4)(x-2)$

= $x^3-2x^2-4x+8$ via FOIL

6 0

2 years ago

PLEASE HELP ME!!! THANK YOU SO MUCH!

monitta

Answer: B / 2,6,10,14,18

Step-by-step explanation:

you were given the equation next input 1 for n.

Solve and a = 2

Then you input 2 for n. Solve and you get a =6.

Do this up until you get to 5.

6 0

2 years ago